SAT 代数・上級数学 練習問題

Advanced Math / Systems Nonlinear Equations

Line-parabola intersections

A line-parabola system can be solved by setting the two expressions for $y$ equal. The resulting quadratic tells how many intersection points exist.

Least you need to know

  • Two real roots give two intersections.
  • One repeated root gives one intersection.
  • No real roots give no real intersection points.

Key notation

  • D — The discriminant $b^2-4ac$ of a quadratic

Worked example

If $x^2=2x+8$, then $x^2-2x-8=0$, or $(x-4)(x+2)=0$. The graphs intersect at two $x$-values.

Common mistakes

  • A repeated root is one solution, not two distinct points.
  • A line and a parabola cannot intersect in more than two points.

How to recognize it

  • A system includes one linear equation and one quadratic equation.
  • The answer choices are numbers of solutions or parameter conditions.

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