Questions d’entraînement SAT en algèbre et mathématiques avancées

Advanced Math / Systems Nonlinear Equations

Line-parabola intersections

A line-parabola system can be solved by setting the two expressions for $y$ equal. The resulting quadratic tells how many intersection points exist.

Least you need to know

  • Two real roots give two intersections.
  • One repeated root gives one intersection.
  • No real roots give no real intersection points.

Key notation

  • D — The discriminant $b^2-4ac$ of a quadratic

Worked example

If $x^2=2x+8$, then $x^2-2x-8=0$, or $(x-4)(x+2)=0$. The graphs intersect at two $x$-values.

Common mistakes

  • A repeated root is one solution, not two distinct points.
  • A line and a parabola cannot intersect in more than two points.

How to recognize it

  • A system includes one linear equation and one quadratic equation.
  • The answer choices are numbers of solutions or parameter conditions.

Prochaine leçon recommandée

Essayez ensuite Absolute value as distance and solution counts pour un rappel proche.

Absolute value as distance and solution counts

Leçons liées

Continuez avec des leçons proches dans le même thème.

Autres façons d’explorer

Commencer l’entraînement